How much NO(g) would form if 513.4*J were pumped into the reaction?

1 Answer
anor277
Dec 19, 2016

The data for the question are not complete.

Explanation:

1/2N_2 + 1/2O_2 rarr NO
DeltaH_"rxn"=+513.4*J

However, we don't know how much nitrogen or oxygen were involved in the reaction. We know the heat absorbed, but so far we have no idea of the thermodynamic data for the reaction.

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