How much #NO(g)# would form if #513.4*J# were pumped into the reaction?

1 Answer
Dec 19, 2016

Answer:

The data for the question are not complete.

Explanation:

#1/2N_2 + 1/2O_2 rarr NO#
#DeltaH_"rxn"=+513.4*J#

However, we don't know how much nitrogen or oxygen were involved in the reaction. We know the heat absorbed, but so far we have no idea of the thermodynamic data for the reaction.