# Question #a40d8

##### 2 Answers

see explanation.

#### Explanation:

Let

Given

Sine Law :

Given

Hence,

Given ABC a triangle where [AD] is the median and let the segment line [BE] which meets [AD] at F and [AC] at E If we assume that AE=EF, we are to show that AC=BF.

**Construction**

AD is extended up to G such that

**Proof**

Now in quadrilateral

In

Again

So

So

Again

Hence