# Is hydroxide ""^(-)"OH" or "HO"^(-)?

Depending on how you draw an entire molecule that contains $\text{^(-)"OH}$, you may want to draw it as ${\text{HO}}^{-}$ to emphasize that that's how the structure is drawn, but there is no set rule saying it must be $\text{^(-)"OH}$ instead of ${\text{HO}}^{-}$.
You can write methanol as $\text{CH"_3"OH}$ to emphasize that the $- \text{OH}$ is drawn as $- \text{O"-"H}$ instead of $\text{H"-"O} -$:
Or, you can write ethanediol as $\text{HOCH"_2"CH"_2"OH}$ to emphasize that the structure is $\text{H"-"O"-"CH"_2-"CH"_2-"O"-"H}$: