# Question 25175

Jan 2, 2017

The volume of the gas is 1.28 × 10^2color(white)(l) "mL".

#### Explanation:

This appears to be a Boyle's Law problem.

Boyle's Law is

$\textcolor{b l u e}{\overline{\underline{| \textcolor{w h i t e}{\frac{a}{a}} {P}_{1} {V}_{1} = {P}_{2} {V}_{2} \textcolor{w h i t e}{\frac{a}{a}} |}}} \text{ }$

We can rearrange Boyle's Law to get

P_1 = P_2 × V_2/V_1#

In this problem,

${P}_{1} = \text{?"; color(white)(mmmll)V_1 = 5.5 × 10^2 "mL}$
${P}_{2} = \text{101 kPa"; color(white)(l) V_2 = 7.0 × 10^2 "mL}$

${P}_{1} = \text{101 kPa" × (7.0 ×10^2 color(red)(cancel(color(black)("mL"))))/(5.5 × 10^2 color(red)(cancel(color(black)("mL")))) = 1.3 × 10^2 color(white)(l)"kPa}$ (2 significant figures)