Question

Question #25175

Answer 1

The volume of the gas is `1.28 × 10^2color(white)(l) "mL"`.

Explanation:

This appears to be a Boyle's Law problem.

Boyle's Law is

`color(blue)(bar(ul(|color(white)(a/a)P_1V_1 = P_2V_2color(white)(a/a)|)))" "`

We can rearrange Boyle's Law to get

`P_1 = P_2 × V_2/V_1`

In this problem,

`P_1 = "?"; color(white)(mmmll)V_1 = 5.5 × 10^2 "mL"`
`P_2 ="101 kPa"; color(white)(l) V_2 = 7.0 × 10^2 "mL"`

∴ `P_1 = "101 kPa" × (7.0 ×10^2 color(red)(cancel(color(black)("mL"))))/(5.5 × 10^2 color(red)(cancel(color(black)("mL")))) = 1.3 × 10^2 color(white)(l)"kPa"` (2 significant figures)