Question #25175

1 Answer
Jan 2, 2017

Answer:

The volume of the gas is #1.28 × 10^2color(white)(l) "mL"#.

Explanation:

This appears to be a Boyle's Law problem.

Boyle's Law is

#color(blue)(bar(ul(|color(white)(a/a)P_1V_1 = P_2V_2color(white)(a/a)|)))" "#

We can rearrange Boyle's Law to get

#P_1 = P_2 × V_2/V_1#

In this problem,

#P_1 = "?"; color(white)(mmmll)V_1 = 5.5 × 10^2 "mL"#
#P_2 ="101 kPa"; color(white)(l) V_2 = 7.0 × 10^2 "mL"#

#P_1 = "101 kPa" × (7.0 ×10^2 color(red)(cancel(color(black)("mL"))))/(5.5 × 10^2 color(red)(cancel(color(black)("mL")))) = 1.3 × 10^2 color(white)(l)"kPa"# (2 significant figures)