Question #de290 Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Suren Abreu Jan 3, 2017 #x=2/3# or #x=-2 1/2# Explanation: #6x^2+11x=10# Subtract #10# from each side. #6x^2+11x-10=0# Factorise. #6x^2+15x-4x-10=0# #3x(2x+5)-2(2x+5)=0# #(3x-2)(2x+5)=0# #3x-2=0# or #2x+5=0# #x=2/3# or #x=-5/2=-2 1/2# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 929 views around the world You can reuse this answer Creative Commons License