How do you express #7/12# as a decimal representation?

1 Answer
Jan 13, 2017

#7/12 = 0.58333... = 0.58bar(3)#

Explanation:

Long divide #7# by #12#...

#color(white)(00000")")underline(color(white)(0)0color(black)(.)5color(white)(0)8color(white)(0)3color(white)(0)3color(white)(.)...)#
#color(white)(00)12color(white)(0)")"color(white)(0)7color(black)(.)0color(white)(0)0color(white)(0)0color(white)(0)0color(white)(.)...#
#color(white)(00000")"0)underline(6color(white)(.)0)#
#color(white)(00000")"0)1color(white)(.)0color(white)(0)0#
#color(white)(00000")"0)underline(color(white)(0)color(white)(.)9color(white)(0)6)#
#color(white)(00000")"00)color(white)(.)color(white)(00)4color(white)(0)0#
#color(white)(00000")"00)color(white)(.)color(white)(00)underline(3color(white)(0)6)#
#color(white)(00000")"00)color(white)(.)color(white)(0000)4color(white)(0)0#
#color(white)(00000")"00)color(white)(.)color(white)(0000)underline(3color(white)(0)6)#
#color(white)(00000")"00)color(white)(.)color(white)(000000)4color(white)(.)...#

Note that the remainder #4# starts repeating, so the quotient does too.

So:

#7/12 = 0.58333... = 0.58bar(3)#