Question

If `pOH=10.75`, what is the concentration of `[HO^-]` in the solution?

Answer 1

`[HO^-]=1.78xx10^-11*mol*L^-1.`

Explanation:

`pOH=-log_10[HO^-]`

If `pOH=10.75`, then `[HO^-]=10^(-10.75)=1.78xx10^-11*mol*L^-1.`

What are `pH`, and `[H_3O^+]` in this solution?