If pOH=10.75, what is the concentration of [HO^-] in the solution?

Jan 10, 2017

$\left[H {O}^{-}\right] = 1.78 \times {10}^{-} 11 \cdot m o l \cdot {L}^{-} 1.$
$p O H = - {\log}_{10} \left[H {O}^{-}\right]$
If $p O H = 10.75$, then $\left[H {O}^{-}\right] = {10}^{- 10.75} = 1.78 \times {10}^{-} 11 \cdot m o l \cdot {L}^{-} 1.$
What are $p H$, and $\left[{H}_{3} {O}^{+}\right]$ in this solution?