Question

Question #3119b

Answer 1

`=2/3(x+1)^(3/2)+c`

Explanation:

`int(x+1)^(1/2)dx`
Let say `u=(x+1)`,then
`(du)/dx=1`
`du=dx`

replace `(x+1) = u` and `dx=du` in the `int(x+1)^(1/2)dx`
`int(x+1)^(1/2)dx`=`intu^(1/2)du`
`=u^(1/2+1)/(1/2+1)+c`
`=u^(3/2)/(3/2)+c`

`=2/3u^(3/2)+c`
replace `( x+1)` in `u`
`=2/3(x+1)^(3/2)+c`