Question #dd63d

1 Answer
Jan 17, 2017

$2 C a \left(g\right) + {O}_{2} \left(g\right) \to 2 C a O \left(s\right)$

As per above balanced equation of the reaction we see that 2mol or $2 \cdot 40 = 80 g$ Ca reacts with 1mol or $32 g {O}_{2}$ to produce $112 g$ CaO.

The given condition is that two reactants to be taken in equal mass and exactly $112 g$ CaO is to be produced conumuing one reactant completely.

It is obvious that 80g Ca and 32g must be taken to produce 112g CO. If 80g of each reactant is taken to react then Ca will be consumed completely as limiting reactant and $\left(80 - 32\right) = 48 g {O}_{2}$ will remain unreacted