Question #a4f96

1 Answer
Aug 19, 2017

Answer:

#F = 21.9# #"N"#

Explanation:

We're not given any information regarding the slope of the incline to determine the gravitational force opposing the motion, nor the friction between the sled and the incline. I will neglect these and assume a simplified work example.

The equation for one-dimensional work is

#ul(W = Fs#

where

  • #W# is the work

  • #F# is the magnitude of the force

  • #s# is the distance it traveled while the force was acting

We know:

  • #W = 379.5# #"J"#

  • #s = 17.3# "#m"#

So we have

#color(red)(F) = W/s = (379.5color(white)(l)"J")/(17.3color(white)(l)"m") = color(red)(ulbar(|stackrel(" ")(" "21.9color(white)(l)"N"" ")|)#

The magnitude of the force she exerted is thus #color(red)(21.9color(white)(l)"newtons"#.