# Question a4f96

Aug 19, 2017

$F = 21.9$ $\text{N}$

#### Explanation:

We're not given any information regarding the slope of the incline to determine the gravitational force opposing the motion, nor the friction between the sled and the incline. I will neglect these and assume a simplified work example.

The equation for one-dimensional work is

ul(W = Fs

where

• $W$ is the work

• $F$ is the magnitude of the force

• $s$ is the distance it traveled while the force was acting

We know:

• $W = 379.5$ $\text{J}$

• $s = 17.3$ "m"

So we have

color(red)(F) = W/s = (379.5color(white)(l)"J")/(17.3color(white)(l)"m") = color(red)(ulbar(|stackrel(" ")(" "21.9color(white)(l)"N"" ")|)

The magnitude of the force she exerted is thus color(red)(21.9color(white)(l)"newtons"#.