Question

Question #36296

Answer 1

`dy/dx=(2-5xy^3)/(5x^2y^2)`

Explanation:

`"differentiate "color(blue)"implicitly with respect to x"`

`"differentiate "-5x^3y^3" using the "color(blue)"product rule"`

`6x-15x^3y^2dy/dx-15x^2y^3=0`

`rArrdy/dx=(15x^2y^3-6x)/(-15x^3y^2)`

`color(white)(rArrdy/dx)=(2-5xy^3)/(5x^2y^2)`