What is the metal oxidation state in #Ni(CO)_4#?

1 Answer
Jan 25, 2017

Answer:

We have zerovalent nickel, i.e. #Ni^(0)#

Explanation:

#"Oxidation number"# is the charge left on the central atom when all the bonding pairs of electrons are removed, with the charge devolved to the most electronegative atom.

For #Ni(CO)_4#, we break the #Ni-CO# bond and we get #Ni^0# #+4xx""^(-):C-=O^+#. And thus nickel has a formal oxidation state of #"ZERO".#

Because #Ni(CO)_4# is quite volatile, its formation forms the basis for the Mond process for nickel purification.