Question #88dab

1 Answer
Mar 24, 2017

Answer:

The magnetic field wil halved.

Explanation:

At the center of the loop, the magnetic field is given by

#B=(mu_o I)/(2r)#

Where

the radius #=r#

and the diameter is #d=2r#

So,

#B=(mu_o I)/(d)#

If we double #d#, that is

#D=2d#

Then,

#B_1=(mu_o I)/(D)=(mu_o I)/(2d)=B/2#

Therefore,

The magnetic field wil be half the value