# Question #88dab

Mar 24, 2017

The magnetic field wil halved.

#### Explanation:

At the center of the loop, the magnetic field is given by

$B = \frac{{\mu}_{o} I}{2 r}$

Where

the radius $= r$

and the diameter is $d = 2 r$

So,

$B = \frac{{\mu}_{o} I}{d}$

If we double $d$, that is

$D = 2 d$

Then,

${B}_{1} = \frac{{\mu}_{o} I}{D} = \frac{{\mu}_{o} I}{2 d} = \frac{B}{2}$

Therefore,

The magnetic field wil be half the value