Question

Question #3b54c

Answer 1

`(3,0)`.

Explanation:

The Graph `G` of the given function `f` is,

`G_f={(x ,y)| y=f(x)=2x-6} sub RR^2`.

Recall that, `X"-axis "= G_X={(x,y)|y=0} sub RR^2`.

So, to find the point of intersection of `G_f and G_X, i.e., G_fnnG_X`, we let, `y=0" in "y=2x-6," giving, "x=3.`

We readily have, `y=0.`

Hence, `G_fnnG_X={(3,0)}.`