# Question #ce46f

##### 1 Answer

#### Explanation:

The key to this problem is the **specific heat** of olive oil, which is said to be equal to

#c_"olive oil" = "2.19 cal g"^(-1)""^@"C"^(-1)#

As you know, the **specific heat** of a substance tells you how much heat must be added to

In your case, you must add **for every**

Now, the first thing to do here is to figure out how much heat is needed in order to increase the temperature of

#55.0 color(red)(cancel(color(black)("g"))) * "2.19 cal"/(1color(red)(cancel(color(black)("g"))) * 1^@"C") = "120.45 cal"^@"C"^(-1)#

This means that in order to increase the temperature of

Consequently, adding

#877 color(red)(cancel(color(black)("cal"))) * overbrace( (1^@"C")/(120.45color(red)(cancel(color(black)("cal")))))^(color(blue)("for 55.0g of olive oil")) = 7.28^@"C"#

Therefore, the final temperature of the olive oil will be

#color(darkgreen)(ul(color(black)(T_"final" = 26.0^@"C" + 7.28^@"C" = 33.3^@"C")))#

The answer is rounded to three **sig figs**.