How do you solve #2x + 3 = 63#?

1 Answer
Jan 25, 2017

Answer:

See the entire solution process below:

Explanation:

First, subtract #color(red)(3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x + 3 - color(red)(3) = 63 - color(red)(3)#

#2x + 0 = 60#

#2x = 60#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 60/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 30#

#x = 30#