Question #4e7fa

1 Answer
Jan 27, 2017

#0 <=theta<=pi/3 and 5/3 pi<=theta<=2 pi#

Explanation:

#r=3 cos theta and r=2-cos theta#.

#3 cos theta =2-cos theta#
#4 cos theta = 2#
#cos theta = 1/2#

#theta = pi/3 = 60^0 and 5/3pi = 300^0# for #0 <= theta <= 2 pi#

If we plot a graph, we can find that the region cover the inside #r=3 cos theta# and #r= 2-cos theta# are #0 <=theta<=pi/3 and 5/3 pi<=theta<=2 pi# for #0<=theta<=2 pi#