Question #c4606

1 Answer

Answer:

#"24 L"#

Explanation:

NIST uses a temperature of #20^@"C"# #("293.15 K"#, #68^@"F")# and an absolute pressure of #"1 atm"# #("14.696 psi"#, #"101.325 kPa")#. This standard is also called normal temperature and pressure (abbreviated as NTP).

Normal Temperature and Pressure

#"T = 293.15K"#
#P = 1 atm#

so

The only difference between STP and NTP is that NTP conditions are at #20^@"C" = "293.15 K"#, rather than at #0^@"C" = "273.15 K"#.

Since only the temperature is different, use Charle's Law:

#V_1/T_1 = V_2/T_2#

We have:

#V_1 = 22.41 L #

#T_1 = 273.15 K #

#V_2 = ? larr "This is the volume of 1 mol of a gas at NTP "#

#T_2 = 293.15 K. #

Plugging our information into Charle's Law:

#V_1/T_1 = V_2/T_2#

#=> (22.41 L)/(273.15 K) = V_2/(293.15 K)#

#=> V_2 = (22.41 L)(293.15 K)/(273.15 K) = 24.05 L#

#"Therefore, 1 mol of any gas will occupy about 24 L at NTP."#

Hope this helped