Question #a22d8
1 Answer
Jan 30, 2017
Explanation:
The equation of a line in
#color(blue)"point-slope form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"#
#"here "m=1/6" and "(x_1,y_1)=(-5,4)# Substitute these values into the equation.
#y-4=1/6(x-(-5))#
#rArry-4=1/6(x+5)larrcolor(red)" in point-slope form"# We can distribute the bracket and simplify to obtain another version of the equation.
#y-4=1/6x+5/6#
#y=1/6x+5/6+4#
#rArry=1/6x+29/6larrcolor(red)" in slope-intercept form"#