Question

Question #8df79

Answer 1

`LHS=(1+sectheta)/sectheta`

`=(costheta(1+sectheta))/(costhetasectheta)`

`=(costheta+1)`

`=((1+costheta)(1-costheta))/(1-costheta)`

`=(1-cos^2theta)/(1-costheta)`

`=sin^2theta/(1-costheta)=RHS`