Question #9a072

Question

Question #9a072

1 Answer

Related questions

How do you find the average rate of change of a function from graph?
How do you find the average rate of change of a function between two points?
How do you find the average rate of change of $f (x) = sec (x)$ $f(x) = sec(x)$ from $x = 0$ $x=0$ to $x = \frac{π}{4}$ $x=pi/4$ ?
How do you find the average rate of change of $f (x) = tan (x)$ $f(x) = tan(x)$ from $x = 0$ $x=0$ to $x = \frac{π}{4}$ $x=pi/4$ ?
How do you find the rate of change of y with respect to x?
How do you find the average rate of change of $y = x^{3} + 1$ $y=x^3+1$ from $x = 1$ $x=1$ to $x = 3$ $x=3$ ?
What is the relationship between the Average rate of change of a fuction and derivatives?
What is the difference between Average rate of change and instantaneous rate of change?
What does the Average rate of change of a linear function represent?
What is the relationship between the Average rate of change of a function and a secant line?

Impact of this question

3967 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-25T22:18:08

The average rate of change of $f (x) = x^{3} - x$ $f(x) = x^3 - x$ over the interval $(1, 5)$ $(1,5)$ is 30.

Explanation:

The average rate of change of a function over an interval $(a, b)$ $(a,b)$ is provided by $\frac{f (b) - f (a)}{b - a}$ $(f(b) - f(a))/(b-a)$

So if we plug in your function as $f (x)$ $f(x)$ on the interval (1,5) into the formula, $\frac{f (5) - f (1)}{5 - 1}$ $(f(5) - f(1))/(5-1)$ which is equal to $\frac{({(5)}^{3} - (5)) - ({(1)}^{3} - (1))}{4}$ $(((5)^3-(5)) - ((1)^3-(1)))/4$ .

If you simplify from here, you will get $\frac{120 - 0}{4}$ $(120-0)/4$ which further simplifies to $30$ $30$ .

Science

Math

Humanities

... and beyond

Question #9a072

1 Answer

Explanation:

Related questions

Impact of this question