If the solubility of a gas is #0.5*g*L^-1# at #"1 bar"# gas pressure, what will be its solubility at #"3 bar"# gas pressure?

1 Answer
Feb 2, 2017

Answer:

Approx. #1.5*g*L^-1#...........

Explanation:

#"Henry's Law"# relates to the solubility of a gas in a liquid. At a given temperature, the solubility of the gas is proportional to the partial pressure of the gas above the liquid.

i.e. #"Gas solubility"# #prop# #P_"gas"#

Or, #"Gas solubility"# #=# #k_"P"P_"gas"#, where #k_"P"# is the socalled #"Henry's Law gas constant"#.

And thus, #P_"initial solubility"=kxx1*"bar"=0.5*g*L^-1#.

#P_"solubility at elevated pressure"=kxx3*"bar"=1.5*g*L^-1#.