Question #8982d Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer P dilip_k Feb 6, 2017 LHS= (cos2x + sin^2x)/cot^2x = (cos^2x-cancel(sin^2x) + cancel(sin^2x))/(cos^2x/sin^2x) =cos^2x xxsin^2x/ cos^2x =sin^2x=RHS Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove \csc \theta \times \tan \theta = \sec \theta? How do you prove (1-\cos^2 x)(1+\cot^2 x) = 1? How do you show that 2 \sin x \cos x = \sin 2x? is true for (5pi)/6? How do you prove that sec xcot x = csc x? How do you prove that cos 2x(1 + tan 2x) = 1? How do you prove that (2sinx)/[secx(cos4x-sin4x)]=tan2x? How do you verify the identity: -cotx =(sin3x+sinx)/(cos3x-cosx)? How do you prove that (tanx+cosx)/(1+sinx)=secx? How do you prove the identity (sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)? See all questions in Proving Identities Impact of this question 1146 views around the world You can reuse this answer Creative Commons License