Question

How do we differentiate `f(x)=tan^3x`?

Answer 1

Derivative is `3tan^2xsecx`

Explanation:

We can use chain rule here,

as if `f(x)=g(x)^3` and `g(x)=tanx`, therefore `f(x)=tan^3x`

Hence, `(df)/(dx)=(df)/(dg)xx(dg)/(dx)`

= `3(g(x))^2xxsecx`

= `3tan^2xsecx`