Question #2b1f4

1 Answer
Feb 10, 2017

Answer:

#2.0xx10^3" Pa"#

Explanation:

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As shown in the figure bottom face of the sample is held rigidly bound and a shearing/tangential force #F# is applied on upper face of area #A#. The modulus of rigidity #G# is defined as the ratio of shear stress to the shear strain.

Shear stress#=F/A# and
shear strain #=tan theta=(Deltax)/l#
#Delta x# is the transverse displacement of the area on which force is acting and #l# is the initial length of the side.

#G -= "Shear stress"/"Shear strain"= (F / A)/ ((Δ x) / l)#
#=>G= (F l)/( A Δ x)" Pa"#

Inserting given values in SI units we get

#G= 10 xx(10/100)/( 0.05/100)#
#=>G= 10 xx(10)/( 0.05)#
#=>G=2.0xx10^3" Pa"#