Question #7273c

1 Answer
Mar 6, 2017

Answer:

#7J#

Explanation:

For a constant force, we say that work, #W#, is:

#W = mathbf F cdot Delta mathbf r#

Here, assuming you mean the particle ends up at #mathbf r = (x,y,z) = (2, -1, 0)#, this means that:

#W = ((5),(3),(2)) cdot ((2-0),(-1-0),(0-0)) = 5(2) + 3(-1) + 2(0) = 7J#

I don't wish to complicate this, but we have assumed that the particle moves in a straight line. We do not need to make that assumption as the field is conservative. It just simplifies the calculation.