# Question #06db0

Feb 8, 2017

$\frac{2 a}{3}$

#### Explanation:

$\frac{\cancel{3} a}{\cancel{4}} ^ 1 \times {\cancel{8}}^{2} / {\cancel{9}}^{3}$

$\therefore = \frac{a}{1} \times \frac{2}{3}$

$\therefore = \frac{2 a}{3}$

No solution for $\frac{3 a}{4} - \frac{8}{9}$

I think there is something missing in the question