# How do you simplify 35/6 + 7/12 - 1 1/3?

Jun 4, 2018

Make all fractions improper, make the denominators the same, perform the addition and subtraction.

#### Explanation:

First, make the third fraction improper by multiplying $3$ by $1$ and adding $1$. So, it will turn out to be

$1 \frac{1}{3} = \frac{3 \times 1 + 1}{3} = \frac{4}{3}$

So $12$ will be our common denominator.

Multiply $\frac{35}{6}$ times $\frac{2}{2}$ in order to make the denominator equal to twelve. Likewise, multiply $\frac{4}{3}$ times $\frac{4}{4}$ to make the denominator equal to twelve.

$\frac{35}{6} \times \frac{2}{2} = \frac{70}{12}$

$\frac{4}{3} \times \frac{4}{4} = \frac{16}{12}$

Once this is done, you have all your fractions under a common denominator, and you can now add and subtract.

$\frac{70}{12} + \frac{7}{12} - \frac{16}{3} = \frac{70 + 7 - 16}{12} = \frac{61}{12}$

This result cannot be simplified further as $61$ and $12$ do not have common factors. So, your result would end up being $\frac{61}{12}$.

Jun 5, 2018

$\frac{61}{12} \mathmr{and} 5 \frac{1}{12}$

#### Explanation:

$\frac{35}{6} + \frac{7}{12} - 1 \frac{1}{3}$

$\therefore = \frac{35}{6} + \frac{7}{12} - \frac{4}{3}$

$\therefore = \frac{70 + 7 - 16}{12}$

$\therefore = \frac{61}{12} \mathmr{and} 5 \frac{1}{12}$