Question

Question #f37c0

Answer 1

`sec^2theta`

Explanation:

Given expression is
`secthetaxxtantheta/sintheta`

rewriting in terms of `sin and cos` we get
`1/costhetaxx(sintheta)/costhetaxx1/sintheta`
`=> 1/costhetaxx1/costheta`
`=> 1/cos^2theta`
`=> sec^2theta`