Question #2a998 Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Feb 10, 2017 sin x = 2/3 cos^2 x = 1 - sin^2 x = 1 - 4/9 = 5/9 --> cos x = - sqrt5/3 (because cos x < 0) tan x = sin/(cos) = (2/3)(-3/sqrt5) = - 2/sqrt5 = - (2sqrt5)/5 cot x = 1/(tan) = - sqrt5/2 sec x = 1/(cos) = - 3/sqrt5 = - (3sqrt5)/5 csc x = 1/(sin) = 3/2 Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 1249 views around the world You can reuse this answer Creative Commons License