Silver nitrate. 9.11g Silver chloride.
First convert the given quantities of compounds to moles. Then apply the balanced equation. 10.8g
0.1276L * 0.500mol/L = 0.0638 moles
So, we have almost equal molar quantities of each reactant, but the reaction equation shows that TWO moles of
The maximum products that can be formed are ONE mole of AgCl for every ONE mole of
0.0635mol * 143.5g/mol = 9.11g AgCl.