Question

Question #36416

Answer 1

`LHS=( secθ+tanθ)/(cotθ+cosθ)`

`=( 1/costheta+sinθ/costheta)/(costheta/sintheta+cosθ)`

`=( 1/costheta(1+sinθ))/(costheta(1/sintheta+1)`

`=( 1/costheta(1+sinθ)sintheta)/(costheta(1+sintheta)`

`=sintheta/cos^2theta!=RHS`