# Question #0074b

I think the correct exponential model would be $y = 5 \cdot {1.44}^{x}$?
Most population problems utilize an exponential model $y = a \cdot {b}^{x}$ for the equation. In order to find the initial population, the number that is the multiplier "a", is the initial population. It could be 5 million or just five. (You need to get the units from the problem)
Algebraically, you can also substitute x = 0 for the amount of time that has passed (initial time = 0), thus giving $y = 5 \cdot {1.44}^{0}$, or y = 5.