# A #100*mL# volume of #2.0*mol*L^-1# hydrochloric acid titrated a sample of metal carbonate. What is the equivalent weight of the metal?

##### 3 Answers

The equivalent weight of the metal is

#### Explanation:

First we need a chemical equation:

Given the equation, the

Equivalent weight of metal is 20 g/eq

#### Explanation:

For HCl

Molarity = Normality

Gram equivalents of HCl = Normality × Volume in litres

For complete neutralisation

Gram equivalents of HCl = Gram equivalents of metal carbonate

Equivalent weight of metal carbonate

Equivalent weight of carbonate

Equivalent weight of metal carbonate = Equivalent weight of metal + Equivalent weight of carbonate

50 g/eq = x + 30 g/eq

x = 20 g/eq

∴ Equivalent weight of metal is 20 g/eq

The number of moles of

So the mass of

Now we know from **the law of equivalent proportion** that the ratio of masses of two reacting substances for neutralization is equal to the ratio of their equivalent masses.

Hence we can say

**Please note**

Equivalent mass of