How do you solve the system of equations #x + 5y = 5# and #x = 4 - 5y#?

1 Answer
Feb 18, 2017

Answer:

See the entire solution process below:

Explanation:

Step 1) Solve the first equation for #x#:

#x + 5y = 5#

#x + 5y - color(red)(5y) = 5 - color(red)(5y)#

#x + 0 = 5 - 5y#

#x = 5 - 5y#

Step 2) Substitute #5 - 5y# for #x# in the second equation and solve for #y#:

#x = 4 - 5y# becomes:

#5 - 5y = 4 - 5y#

#5 - 5y + color(red)(5y) = 4 - 5y + color(red)(5y)#

#5 - 0 = 4 - 0#

#5 != 4#

Because #5# does not equal #4# there is no solution to this question or the solution is #x# and #y# equal the null set: #{O/}#