Question

Question #56c6f

Answer 1

`tan2x-cot2x`

`=(sin2x)/(cos2x)-(cos2x)/(sin2x)`

`=(sin^2 2x-cos^2 2x)/(sin2xcos2x)`

`=-(2(cos^2 2x-sin^2 2x))/(2*sin2xcos2x)`

`=-(2cos4x)/(sin4x)`

`=-cot4x`