Question

Question #8e83b

Answer 1

`"Mercuric bromide........."`

Explanation:

Or `"mercury(II) bromide"`. And `Hg_2Br_2` is `"mercurous bromide"`. What are the oxidation states of mercury in each salt?

Answer 2

`"HgBr"_2"` is mercury (II) bromide.

Explanation:

Since bromide anions always have a `1^(-)` charge, and there are two bromide ions in the formula, the overall charge for the bromide part of the compound is `2^(-)`. This compound is neutral, which means that the mercury cation must have a `2^(+)` charge, and is therefore the mercury (II) cation.

Therefore, `"HgBr"_2"` is mercury (II) bromide.

If you go to the following site, you will see that `"HgBr"_2"` has many names, but usually it is called mercury (II) bromide. https://pubchem.ncbi.nlm.nih.gov/compound/24612#section=Top