# Question 8e83b

##### 2 Answers
Feb 21, 2017

$\text{Mercuric bromide.........}$

#### Explanation:

Or $\text{mercury(II) bromide}$. And $H {g}_{2} B {r}_{2}$ is $\text{mercurous bromide}$. What are the oxidation states of mercury in each salt?

Feb 21, 2017

$\text{HgBr"_2}$ is mercury (II) bromide.

#### Explanation:

Since bromide anions always have a ${1}^{-}$ charge, and there are two bromide ions in the formula, the overall charge for the bromide part of the compound is ${2}^{-}$. This compound is neutral, which means that the mercury cation must have a ${2}^{+}$ charge, and is therefore the mercury (II) cation.

Therefore, $\text{HgBr"_2}$ is mercury (II) bromide.

If you go to the following site, you will see that $\text{HgBr"_2}$ has many names, but usually it is called mercury (II) bromide. https://pubchem.ncbi.nlm.nih.gov/compound/24612section=Top