Question

Question #b623c

Answer 1

`theta = n pi` where `n =` all integers

Explanation:

Find a common denominator: `1/cos theta - cos^2 theta/cos theta = (1-cos^2 theta)/ cos theta`

Set the function `=0`

From the denominator: `cos theta = 0` gives asymptotes

From the numerator you find the zeros:

`1-cos^2 theta = 0; cos^2 theta = 1; cos theta =+-1`

This occurs at `theta = ..., -2pi, -pi, 0, pi, 3pi, ...`

So `theta = n pi` where `n =` all integers