How do you solve #\cos^2 x = \frac{1}{16} # over the interval #[0,2pi]#?

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Nghi N Share
Apr 21, 2018

Answer:

#x = +- 75^@52#

Explanation:

#cos^2 x = 1/16#
#cos x = +- 1/4#
Calculator and unit circle give -->
#x = +- 75^@52#

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Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

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1
Apr 20, 2018

Answer:

#x=cos^(-1)(1/4)=1.32 ["rad"]=75.5°#

Explanation:

#cos^2(x)=1/16#
#cos(x)=1/4#
#x=cos^(-1)(1/4)=1.32 ["rad"]=75.5#

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