How do you solve #\cos^2 x = \frac{1}{16} # over the interval #[0,2pi]#?
preview
×

Edit wording or topicUpdate the question or its topic
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?
Answer
Write a one sentence answer...
Answer:
Explanation
Explain in detail...
Explanation:
I want someone to double check my answer
 Show activity

Someone from Walnut, United States requested an answer.