If the length of a rectangle is #4# cm. more than its width and the perimeter of the rectangle is #28# cm., what is the area of the rectangle?

1 Answer

#"Area" = 45 " cm"^2#

Explanation:

Let the length be #L#
and the width be #W# (with all measurements in cm.)

We are told that #L=W+4#
and
that the perimeter is #28#

Since the perimeter of a rectangle is #2(L+W)#
we have
#color(white)("XXX")2(L+W)=28#

#color(white)("XXX")2(W+4+W)=28#

#color(white)("XXX")2(2W+4)=28#

#color(white)("XXX")(2W+4)=14#

#color(white)("XXX")2W=10#

#color(white)("XXX")W=5#

and since #L=W+4#
#color(white)("XXX")L=9#

Finally
#color(white)("XXX")"Area" = L xx W = 9 xx 5 =45# (sq.cm.)