You have passed 18000 coulombs of charge through the cell, with the result the 0.0935 mol (5.93 g) of Cu is produced.
A 5-amp current is the result of 5 coulombs of charge passing through the cell every second. In one hour (3600 s) this will amount to
To change this into "Chemistry units" we need to used the quantity known as a faraday of charge. One faraday of charge is the total charge carried by one mole of electrons, and is equal to 96 350 coulombs.
So, the charge determined above is
The copper ion in
Therefore, the 0.187 mol of electrons devilered during the hour mentioned above will reduce