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Answer 1 · 2017-11-18T00:16:44

#x^2+y^2 = 6/4x+7y#

You will need to know these subsitutions:

#r^2=x^2+y^2#
#cos(theta) = x/r#
#sin(theta) = y/r#

Follow along these steps:

#r = 6/4costheta+7sintheta#

Substitute #costheta# and #sintheta# with their appropriate substitutions.

#r = 6/4*x/r+7*y/r#

Multiply both sides by #r#

#r^2 = 6/4x+7y#

Substitute #r^2# with it's appropriate substitution

#x^2+y^2 = 6/4x+7y#

This is a valid rectangular equation.