# How do I convert polar coordinates (6, 60^circ) to rectangular coordinates?

Sep 11, 2014

$r a \mathrm{di} u s = r = 6$

$\theta = 60$ degrees

Make appropriate substitutions for $r$ and $\theta$

$x = r \cos \left(\theta\right) \to 6 \cos \left(60\right) = 6 \cdot \frac{1}{2} = 3$

$y = r \sin \left(\theta\right) \to 6 \sin \left(60\right) = 6 \cdot \frac{\sqrt{3}}{2} = 3 \sqrt{3}$

Solution: $\left(3 , 3 \sqrt{3}\right)$

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