Question #a62eb

Mar 8, 2017

$5 {x}^{4} - 5 {x}^{3} - 10 {x}^{2}$
Create the factors that make the equation = $0$
$\left(x - 2\right) \left(x + 1\right) = {x}^{2} - x - 2 = 0$
To get the leading term to $= 5 {x}^{4}$, multiply the factors by $5 {x}^{2}$ since we already have an ${x}^{2}$, remembering that ${x}^{m} {x}^{n} = {x}^{m + n}$:
$5 {x}^{2} \left(x - 2\right) \left(x + 1\right) = 5 {x}^{2} \left({x}^{2} - x - 2\right) = 5 {x}^{4} - 5 {x}^{3} - 10 {x}^{2}$