Question #d280e

1 Answer
Apr 26, 2017

Answer:

#1000m#

Explanation:

Distance traveled #s# in time #t#. Applicable kinematic equation is
#s=ut+1/2at^2#
where #a# is acceleration and #u# is initial velocity.

Car a
#s_a=0xx60+1/2(0.75)(60)^2#
#s_a=1350m#

Car b
#s_b=0xx60+1/2(0.25)(60)^2#
#s_a=450m#

Difference is #=1350-450=900m#
When cars started Car a was ahead of Car b by#=100m#
After #1min# Car a is ahead of Car b by#=900+100m=1000m#