If pH=8.19, what is [H_3O^+]?

Mar 7, 2017

$p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$, so $\left[{H}_{3} {O}^{+}\right] = 6.00 \times {10}^{-} 9 \cdot m o l \cdot {L}^{-} 1$.

Explanation:

We know that $p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$

So that if $p H = 8.19$, $\left[{H}_{3} {O}^{+}\right] = {10}^{- 8.19}$

$6.00 \times {10}^{-} 9 \cdot m o l \cdot {L}^{-} 1$

Would this solution be basic or acidic?