Question #fcdaf

1 Answer
Mar 8, 2017

Answer:

#log(1)=0#

Explanation:

A logarithm is used solve for the exponent of a base that results in a certain value.

Given:

#a^x=y#

then,

#log_a(y)=x#

For a generic 'log' function, it is assumed to be base 10. So, we have the following:

#log(1)# is like saying #10^x=1#

For any base, including 10, raised to the power 0, the result is 1. Therefore, #log(1)=0#