Question

Question #58423

Answer 1

52.7g NaCl

Explanation:

First convert the given quantities of compounds to moles. Then apply the balanced equation. 50g `FeCl_3` is 50/161 = 0.31 mole (you didn’t specify Fe(II) or Fe(III)). 50g `Na_3PO_4` is 50/164 = 0.30 mole (Specific form also not specified).

`FeCl_3` + `Na_3PO_4` → `FePO_4` + `3NaCl`

So, we have almost equal molar quantities of each reactant. The reaction equation shows that one mole of `FeCl_3` reacts with one mole of `Na_3PO_4`. The maximum products that can be formed are one mole of `FePO_4` and three moles of NaCl for every one mole of `FeCl_3` . This reaction would produce 0.30 * 3 = 0.9 moles of sodium chloride.
0.9 mol * 58.5g/mol = 52.7g NaCl.