Question

Question #142e0

Answer 1

`rArr costheta = 5/sqrt61`

Explanation:

`tan theta= -6/5`

Using the identity in trigonometry,
`1 + tan^2 theta= sec^2theta`

`rArr 1+36/25= sec^2theta`

`rArr 61/25= sec^2theta`

`rArr sectheta = sqrt61/5`

Also, `cos theta= 1/sec theta`

`rArr costheta = 5/sqrt61`