Question #3e169

1 Answer
Jul 10, 2017

Answer:

#a_x = 1.23# #"m/s"^2#

Explanation:

I'll assume he started from rest, and the acceleration is constant.

We can solve this problem using the kinematics equation

#v_x = v_(0x) + a_xt#

where

  • #v_x# is the velocity (one-dimensional) at time #t#

  • #v_(0x)# is the initial velocity

  • #a_x# is the constant acceleration

  • #t# is the time

He starts with an initial velocity of #0# (assuming he started from a state of rest), so plugging in known values, we have

#11.1# #"m/s"# #= 0 + a_x"("9# #"s)"#

#a_x = color(red)(1.23# #color(red)("m/s"^2#

His (assumed to be constant) acceleration is thus #color(red)(1.23# #sfcolor(red)("meters per second per second"#.