Question

Question #3e169

Answer 1

`a_x = 1.23` `"m/s"^2`

Explanation:

I'll assume he started from rest, and the acceleration is constant.

We can solve this problem using the kinematics equation

`v_x = v_(0x) + a_xt`

where

• `v_x` is the velocity (one-dimensional) at time `t`

• `v_(0x)` is the initial velocity

• `a_x` is the constant acceleration

• `t` is the time

He starts with an initial velocity of `0` (assuming he started from a state of rest), so plugging in known values, we have

`11.1` `"m/s"` `= 0 + a_x"("9` `"s)"`

`a_x = color(red)(1.23` `color(red)("m/s"^2`

His (assumed to be constant) acceleration is thus `color(red)(1.23` `sfcolor(red)("meters per second per second"`.